Question

What is C ?
⁸ ⁶
A. 10
B. 28
C. 35
D. 14​

Answer 1

8!/6!•(8-6)

Cancel the factor of 6!

8•7/2!

Multiply and divide

56/2!

Solution
28

Option B

Answer 2

B

Explanation:

assuming you mean
`8C_(6)`

using the definition

n
`C_(r)` =
`(n!)/(r!(n-r)!)`

where n! = n(n - 1)(n - 2) × 3 × 2 × 1

then

8
`C_(6)`

=
`(8!)/(6!(8-6)!)`

=
`(8!)/(6!(2!))`

= (8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / (6 × 5 × 4 × 3 × 2 × 1 × 2 × 1

cancel (6 × 5 × 4 × 3 × 2 × 1 ) on numerator / denominator

= (8 × 7 ) / 2 × 1

= 56 ÷ 2

= 28

Apologies for formatting.