Answer:
Explanation:
You want two numbers that have a sum of 28 such that 4 times the lesser is 7 more than 3 times the greater.
Setup
Let the (lesser, greater) numbers be represented by (x, y).
x + y = 28 . . . . . . their sum is 28
4x -3y = 7 . . . . . . 4 times the lesser is 7 more than 3 times the greater
Solution
Using the first equation to write an expression for x, we have ...
x = 28 -y
Substituting this into the second equation gives ...
4(28 -y) -3y = 7
112 -7y = 7 . . . . . . . . simplify
105 = 7y . . . . . . . . . add 7y-7
15 = y . . . . . . . . . . . divide by 7
x = 28 -15 = 13
The lesser number is 13; the greater number is 15.
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Additional comment
4 times the lesser number is 4·13 = 52.
3 times the greater number is 3·15 = 45.
52 is 7 more than 45, as required.