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Find the values of p and g such that
4x² + 12x = 4(x + p)^2-q

Find the values of p and g such that 4x² + 12x = 4(x + p)^2-q-example-1
User GuRAm
by
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2 Answers

5 votes

Answer:

q=8xp+4p²-12x

Explanation:

its easy

Find the values of p and g such that 4x² + 12x = 4(x + p)^2-q-example-1
User Shivam Bhalla
by
5.9k points
8 votes

The values of p and q are p = 3/2 and q = 9

To solve this problem

Extend the equation's right side as follows:

4x² + 12x = 4(x² + 2px + p²) - q

Combine like terms:

4x² + 12x = 4x² + 8px + 4p² - q

Equate the coefficients of each term on both sides:

• x coefficient: 12 = 8p

• Constant term: -q = 4p²

Solve for p:

• From the x coefficient equation: p = 12/8 = 3/2

Substitute p = 3/2 into the constant term equation:

-q = 4(3/2)²

-q = 4 * 9/4

-q = 9

Solve for q:

q = 9

Therefore, the values of p and q are p = 3/2 and q = 9

User Milla Tidy
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6.6k points