Question

Use reference table G, to determine the type of solution formed when 110g of NaNO3 is dissolved in 100g of water at 45°C.

unsaturated
saturated
supersaturated
suspension

Answer 1

unsaturated is the answer

Answer 2

unsaturated

Step-by-step explanation:

Reference Table G provides solubility guidelines for selected salts in water at 25°C. However, since the temperature in the given problem is 45°C, we need to consult a solubility chart or table that provides solubility data at that temperature.

At 45°C, the solubility of NaNO3 in water is approximately 123 g/100 mL. Therefore, when 110 g of NaNO3 is dissolved in 100 g of water at 45°C, the resulting solution is unsaturated because the amount of solute (110 g) is less than the maximum amount of solute (123 g) that can dissolve in 100 g of water at that temperature.

So, the type of solution formed is unsaturated.