Question

PLSSSS HELP ME!!!!!!!! A classroom is rectangular in shape. If listed as ordered pairs, the corners of the classroom are (−22, 14), (−22, −10), (2, 14), and (2, −10). What is the perimeter of the classroom in feet? 96 feet 176 feet 240 feet 480 feet

Answer 1

120

Explanation:

We can use the distance formula to find the length of each side of the rectangle and then add them up to get the perimeter.

Distance between (-22, 14) and (-22, -10):

d = sqrt[(14 - (-10))^2 + (-22 - (-22))^2] = 24 feet

Distance between (-22, -10) and (2, -10):

d = sqrt[(-10 - (-10))^2 + (2 - (-22))^2] = 24 feet

Distance between (2, -10) and (2, 14):

d = sqrt[(-10 - 14)^2 + (2 - 2)^2] = 24 feet

Distance between (2, 14) and (-22, 14):

d = sqrt[(14 - 14)^2 + (-22 - 2)^2] = 48 feet

Adding up the lengths of all sides, we get:

24 + 24 + 24 + 48 = 120 feet

Therefore, the perimeter of the classroom in feet is 120 feet. Answer: 120 feet.

Answer 2

96

Explanation:

The distance between the two points (-22, 14) and (-22, -10) is 24 units. The distance between the two points (-22, 14) and (2, 14) is 24 units. The distance between the two points (2, 14) and (2, -10) is 24 units. The distance between the two points (2, -10) and (-22, -10) is 24 units. Therefore, the perimeter of the classroom is 24 + 24 + 24 + 24 = 96 feet. The answer is 96 feet.

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