Question

A chemical reaction with a single reactant has a rate constant of 0.1161 s-1. How

long (in seconds) does it take for the reaction to be 72.6% complete? How do you solve this problem?
Ans: 11.2%

Answer 1

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Answer 2

Answer: o solve this problem, we need to use the equation for the rate of a chemical reaction with a single reactant:

rate = k[reactant]

where k is the rate constant, [reactant] is the concentration of the reactant, and rate is the rate of the reaction.

The goal of the problem is to determine how long it takes for the reaction to be 72.6% complete. We can express this as a percentage of the reactant being consumed: 100% - 72.6% = 27.4% of the reactant remains.

We can rearrange the rate equation to solve for time:

time = (1/rate) * (1 - (27.4/100))

Substituting in the given values, we have:

time = (1/0.1161 s-1) * (1 - (27.4/100))

= 8.66 s

Therefore, it takes approximately 8.66 seconds for the reaction to be 72.6% complete.

Note: It is important to make sure to use consistent units when solving this problem. In this case, the rate constant is given in seconds, so the time unit should also be in seconds.