Question

think about a density curve that consists of two line segments. the first goes from the point (0, 1) to the point (0.4, 1). the second goes from (0.4, 1) to (0.8, 2) in the xy-plane. what percent of observations fall between 0.4 and 0.8?

Answer 1

37.5%

Explanation:

Area = (b1 + b2) * h / 2

Area = (1 + 2) * 0.4 / 2 = 0.6

Total area = 0.8 * 2 = 1.6

Percentage of observations between 0.4 and 0.8 = Area of trapezoid / Total area * 100%

= 0.6 / 1.6 * 100%

= 37.5%

Therefore, approximately 37.5% of observations fall between 0.4 and 0.8 on this density curve.