92.5k views
4 votes
7a^4b^2, for a=-2, b=-0.25

1 Answer

2 votes

Answer: To evaluate 7a^4b^2 for a=-2 and b=-0.25, we can substitute these values into the expression and simplify:

7a^4b^2 = 7(-2)^4(-0.25)^2

First, we can simplify the powers of -2 and -0.25:

(-2)^4 = 16

(-0.25)^2 = 0.0625

Substituting these values into the expression, we get:

7a^4b^2 = 7(16)(0.0625)

Simplifying the multiplication, we get:

7a^4b^2 = 7(1)

Finally, we can simplify the expression to get the final answer:

7a^4b^2 = 7

Therefore, when a=-2 and b=-0.25, 7a^4b^2 is equal to 7.

Explanation:

User MoiioM
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories