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a no. 10 steel rebar is tested in tension. by monitoring the load reading of the testing machine, it was found that the specimen yielded at a load of 41,600 lb and fractured at 48,300 lb. a. determine the tensile stresses at yield and at fracture. b. estimate how much increase in

User Apascual
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a. To determine the tensile stresses at yield and at fracture, we need to know the cross-sectional area of the rebar. Let's assume that the cross-sectional area of the rebar is 0.785 square inches (which is the cross-sectional area for a No. 10 steel rebar according to some sources).

The tensile stress at yield is calculated as the yield load divided by the cross-sectional area:

Stress at yield = Yield load / Cross-sectional area = 41,600 lb / 0.785 sq in = 53,011 psi

The tensile stress at fracture is calculated as the fracture load divided by the cross-sectional area:

Stress at fracture = Fracture load / Cross-sectional area = 48,300 lb / 0.785 sq in = 61,508 psi

b. To estimate how much increase in load is required to cause a 1% deformation in the rebar, we need to know the original length of the rebar and the amount of deformation that corresponds to a 1% strain. Let's assume that the original length of the rebar is 12 feet (144 inches) and that a 1% strain corresponds to a deformation of 1.44 inches (which is the amount of deformation for a 12-foot length of rebar subjected to a 1% strain).

To calculate the increase in load required to cause a 1% deformation, we can use the following formula:

Increase in load = Cross-sectional area x Strain x Modulus of elasticity

where the modulus of elasticity for steel is typically around 29,000,000 psi.

Plugging in the values, we get:

Increase in load = 0.785 sq in x 1.44 in / 144 in x 29,000,000 psi = 625.4 lb

Therefore, an increase in load of about 625 lb would be required to cause a 1% deformation in the rebar.
User Tamas Nagy
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