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A weightlifter lifts a 210 kg weight 1.5 m straight up into the air. How much force does he need to use and how much work does he have to do?

User Raj Damani
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Answer:

The work done by the weightlifter is equal to the force applied multiplied by the distance lifted. The force required to lift the weight is equal to its weight (mass x gravity), which is:

F = 210 kg x 9.8 m/s² = 2058 N

The work done is:

W = F x d = 2058 N x 1.5 m = 3087 J

Therefore, the weightlifter needs to apply a force of 2058 N and do 3087 J of work to lift the weight 1.5 m straight up into the air.

User Kirill Ilichev
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