Answer:
f(0)=−7
f(2)=83
f′(x)=27x2+9
Then, there exists a cin (0,2)
such that:
f′(c)=f(2)−f(0)2−0=83+72=45
This means that you have to solve the following:
f′(c)=45⇒27c2+9=45⇒3c2−4=0
Solutions are c=±23√3=±1.1547…
Only c=23√3
is inside the set (0,2)
Step-by-step explanation: I believe this is what you are looking for. my oligopolies if this is incorrect