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Solve for x
(9x-16)
(3x+11)
(7x-5)

Solve for x (9x-16) (3x+11) (7x-5)-example-1
User Kesavan R
by
7.4k points

2 Answers

6 votes

The value of x is 10.

To solve for x in the given triangle, we use the fact that the sum of the interior angles of a triangle is always 180 degrees. Given the angles
\( (9x - 16)^\circ \), \( (3x + 11)^\circ \), and \( (7x - 5)^\circ \), we can set up an equation:


\[ (9x - 16) + (3x + 11) + (7x - 5) = 180 \]

Combining like terms, we get:


\[ 9x + 3x + 7x - 16 + 11 - 5 = 180 \]


\[ 19x - 10 = 180 \]

Adding 10 to both sides:


\[ 19x = 190 \]

Dividing both sides by 19:


\[ x = (190)/(19) \]


\[ x = 10 \]

User Radioaktiv
by
7.7k points
2 votes

Answer:


\huge\boxed{\sf x = 10}

Explanation:

Statement:

  • The measure of internal angles of a triangle adds up to 180 degrees.

Solution:

So,

(9x - 16) + (3x + 11) + (7x - 5) = 180

9x - 16 + 3x + 11 + 7x - 5 = 180

  • Combine like terms

9x + 3x + 7x - 16 + 11 - 5 = 180

19x - 10 = 180

  • Add 10 to both sides

19x = 180 + 10

19x = 190

  • Divide both sides by 19

x = 190/19

x = 10


\rule[225]{225}{2}

User Agis
by
7.4k points

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