We can solve this problem by standardizing the variable x using the formula:
z = (x - μ) / σ
where μ is the mean and σ is the standard deviation. This formula gives us the number of standard deviations x is from the mean.
Substituting the values given in the problem, we get:
z = (92 - 98) / 6 = -1
This means that 92 is one standard deviation below the mean.
To find P(x ≥ 92), we need to find the area under the normal curve to the right of 92. Since we have standardized the variable, we can use a standard normal distribution table or a calculator to find this area.
Using a standard normal distribution table, we look up the area to the right of -1, which is 0.1587. This means that the area to the left of -1 (which corresponds to x < 92) is 1 - 0.1587 = 0.8413.
Therefore, P(x ≥ 92) = 0.8413, which is closest to option C, 0.84.