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Solve for x. Round to the nearest tenth, if necessary.

Solve for x. Round to the nearest tenth, if necessary.-example-1
User MrByte
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1 Answer

4 votes

Answer:


x = 24.4

Explanation:

We arre given a right angled triangle and we are interested in solving out for " x " .

Here we can make use of trigonometric ratios for a right angled triangle.

We can see that the sides involved in the triangle are perpendicular and base therefore we can make use of ratio of tangent .

In a right angled triangle, tangent is ,


\implies \tan\theta =(p)/(b)\\

where,

  • p is perpendicular
  • b is base
  • θ is the angle opposite

And here ,

  • p = 19
  • b = x
  • θ = 38° .
  • tan38° = 0.78

On substituting the respective values, we have;


\implies \tan38^o = (19)/(x) \\


\implies 0.78 =(19)/(x) \\


\implies x = (19)/(0.78)\\


\implies x = 24.35 \\

After rounding off to nearest tenth ,


\implies \boxed{ x = 24.4} \\

Hence the value of x is 24.4 .

User Saokat Ali
by
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