Answer:
To solve this problem, we need to use stoichiometry to determine the amount of NH3 produced from the given amounts of H2 and N2.
From the balanced chemical equation:
3 moles of H2 react with 1 mole of N2 to produce 2 moles of NH3
First, we need to convert the given masses of H2 and N2 into moles:
moles of H2 = 265.8 g / 2.016 g/mol = 132.02 mol
moles of N2 = 92.7 g / 28.014 g/mol = 3.31 mol
Next, we can use the mole ratio from the balanced chemical equation to determine the moles of NH3 produced:
moles of NH3 = (2/3) x 132.02 mol = 88.02 mol
Finally, we can convert the moles of NH3 to grams using the molar mass of NH3:
mass of NH3 = 88.02 mol x 17.031 g/mol = 1498.6 g
Therefore, 1498.6 grams of NH3 are produced.