Question

3. A stone is released from a hot- air balloon which is rising steadily at 4m/s. Find the velocity of the stone after 3 s of release.​

Answer 1

Step-by-step explanation:

Initial velocity = 4 m/s

gravity = - 9.81 m/s^2

Vf = v o + a t

= 4 + ( -9.81)(3) = -25.4 m/s or 25 .4 m/s (downward)