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BCD is a triangle.

ABD is a straight line.
Angle ABC = 124°
Angle BDC = 62°
1249
B
A
Determine what type of triangle BCD is.
Give a reason for each stage of your working.
62
D


SHOW WORKING

BCD is a triangle. ABD is a straight line. Angle ABC = 124° Angle BDC = 62° 1249 B-example-1

1 Answer

2 votes

Answer:

Δ BCD is an isosceles triangle

Explanation:

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ ABC is an exterior angle of the triangle , then

∠ BDC + ∠ BCD = ∠ ABC

62° + ∠ BCD = 124° ( subtract 62° from both sides )

∠ BCD = 62°

then ∠ BDC = ∠ BCD = 62°

thus the 2 base angles of the triangle are congruent

then triangle BCD is isosceles with BC = BD

User Crftr
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