189k views
1 vote
A line has a slope of –12 and passes through the point (6,–9). Write its equation in slope-intercept form.

User Fixagon
by
7.5k points

1 Answer

2 votes

Answer: y = -12x + 63

Explanation:

The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept. We are given the slope of the line, which is -12, and a point that the line passes through, which is (6,-9).

Using the point-slope form of a linear equation, we have:

y - (-9) = -12(x - 6)

Simplifying this equation, we get:

y + 9 = -12x + 72

Subtracting 9 from both sides, we get:

y = -12x + 63

Therefore, the equation of the line in slope-intercept form is y = -12x + 63.

User Rczajka
by
8.1k points