Question

Calcium Carbonate (CaCO₃) thermally decomposes when heated to leave Calcium Oxide and release Carbon Dioxide gas.

CaCO₃ -> CaO + CO₂

Calcium Atoms have a mass of 40, Carbon 12 and Oxygen 16.

If 10.0g Calcium Carbonate is heated what mass of Carbon Dioxide is created?

Answer 1

To calculate the mass of carbon dioxide produced when heating 10.0g of calcium carbonate (CaCO₃), we can use the stoichiometry of the balanced chemical equation:

CaCO₃ -> CaO + CO₂

First, let's determine the molar mass of CaCO₃ and CO₂.

CaCO₃:
Calcium (Ca) = 40 g/mol
Carbon (C) = 12 g/mol
Oxygen (O) = 16 g/mol
Molar mass of CaCO₃ = 40 + 12 + (3 * 16) = 40 + 12 + 48 = 100 g/mol
CO₂:
Carbon (C) = 12 g/mol
Oxygen (O) = 16 g/mol
Molar mass of CO₂ = 12 + (2 * 16) = 12 + 32 = 44 g/mol
Now we'll use stoichiometry to find the mass of CO₂ produced from 10.0g of CaCO₃.

We know that 1 mol of CaCO₃ produces 1 mol of CO₂. First, we'll find the moles of CaCO₃.

moles of CaCO₃ = mass / molar mass
moles of CaCO₃ = 10.0g / 100 g/mol = 0.1 mol

Since the ratio of CaCO₃ to CO₂ is 1:1, 0.1 mol of CaCO₃ will produce 0.1 mol of CO₂. Now, let's find the mass of CO₂ produced.

mass of CO₂ = moles of CO₂ * molar mass of CO₂
mass of CO₂ = 0.1 mol * 44 g/mol = 4.4 g

So, when 10.0g of calcium carbonate is heated, 4.4g of carbon dioxide is produced.