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Solve for n. (X^3)^3<= x^n
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Solve for n.
(X^3)^3<= x^n

User AnkitG
by
7.3k points

1 Answer

3 votes

Answer: n ≥ 9

Explanation:

Using the Law of Exponents, we can simplify x^3^3 to x^9.

Then, since they have the same bases, we can remove them from both sides, leaving us with 9 ≤ n, or n ≥ 9.

User Lynnyi
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