Question

based on the data from the graph, which of the following indicates how much more effective oxygen transport is at the 20 percent carbon monoxide level than the 60 percent carbon monoxide level?

Answer 1

Oxygen transport is more effective at 20 percent carbon monoxide level than at 60 percent because less carbon monoxide at 20 percent allows more oxygen to bind to hemoglobin. Carbon monoxide's higher affinity for hemoglobin than oxygen necessitates the use of pure oxygen in treatments to displace carbon monoxide, and oxygen has a higher affinity for hemoglobin than carbon dioxide.

Step-by-step explanation:

Based on the data from the graph that plots percent oxygen saturation of hemoglobin as a function of oxygen partial pressure, oxygen transport is more effective at the 20 percent carbon monoxide level than at the 60 percent carbon monoxide level because at lower concentrations of carbon monoxide, there is less competition for binding sites on hemoglobin, making it easier for oxygen to bind. Carbon monoxide has a higher affinity for hemoglobin than oxygen, which means the presence of carbon monoxide significantly reduces hemoglobin's oxygen-carrying capacity. Treatment of carbon monoxide poisoning often involves the patient breathing pure oxygen to displace the carbon monoxide from hemoglobin, as depicted in the equilibrium reaction Hb(CO) (aq) + O₂ (g) = Hb(O₂) 1 (aq) + CO (g). Though oxygen and carbon dioxide both can bind to hemoglobin, oxygen has a higher affinity for hemoglobin than carbon dioxide, influencing its effectiveness in oxygen transport at different levels of carbon monoxide exposure.

Answer 2

Based on the data from the graph, the option that indicates how much more effective oxygen transport is a the 20 percent carbon monoxide level than the 60 percent carbon monoxide level is d: 1.9 times more effective.

Based on the data from the graph, oxygen transport is 1.9 times more effective at the 20 percent carbon monoxide level than the 60 percent carbon monoxide level.

To calculate this, one can use the following formula:

(Oxygen saturation at 20% CO) / (Oxygen saturation at 60% CO) = Effectiveness ratio

Therefore, oxygen transport is 1.9 times more effective at the 20 percent carbon monoxide level than the 60 percent carbon monoxide level.

Based on the data from the graph, which of the following indicates how much more effective oxygen transport is at the 20 percent carbon monoxide level than the 60 percent carbon monoxide level? 0.33 times more effective 0.53 times more effective 3 times more effective 1.9 times more effectiv