Question

Chord AC intersects chord BD at point P in circle Z. AP=12 m DP=5 m PC=6 m What is BP?

Answer 1

BP = 14.4

Explanation:

Given 2 chords intersecting inside a circle, then

The products of the measures of the parts of one chord is equal to the product of the measures of the parts of the other chord, that is

BP × DP = AP × PC , that is

BP × 5 = 12 × 6

5BP = 72 ( divide both sides by 5 )

BP = 14.4