Question

2. Convert 3 moles of Ba(NO3)₂ to grams of Ba(NO3)2

Answer 1

Step-by-step explanation:

n = m / Mr

Atomic Mass :

Ba =137 ,327

N = 14,0067

O =15,9994

Mr[(Ba(NO3)2] = 137,327 + (14,0067+15,9994*3)*2 = 261,3368 g/mol

so for finding m[Ba(NO3)2] will take :

n = m / Mr

m = n * Mr

m =3 moles * 261,3368 g/moles

m = 784,01 grams