15.5k views
4 votes
Choose the graph that matches the following system of equations: 5x + 2y = 2 3x − 3y = 18 a A line includes points 0 comma 6 and 2 comma 4. A line includes points 0 comma 2 and negative 2 comma 7. b A line includes points 0 comma 1 and 2 comma negative 4. A line includes points negative 1 comma negative 7 and 0 comma negative 6. c A line includes points 0 comma 1 and 1 comma negative 4. A line includes points 2 comma negative 4 and 0 comma negative 6. d A line includes points 0 comma 6 and 1 comma 3. A line includes points 0 comma 1 and 1 comma 6.

User CitraL
by
8.3k points

1 Answer

4 votes

Answer:

none

Explanation:

To determine which graph matches the given system of equations, we can first solve the system for x and y.

Starting with the system:

5x + 2y = 2

3x - 3y = 18

We can solve for x in terms of y by rearranging the first equation:

5x + 2y = 2

5x = 2 - 2y

x = (2 - 2y)/5

Then we can substitute this expression for x into the second equation:

3x - 3y = 18

3[(2 - 2y)/5] - 3y = 18

6 - 6y - 15y = 90

-21y = 84

y = -4

Now we can substitute this value of y into either equation to solve for x:

5x + 2y = 2

5x + 2(-4) = 2

5x = 10

x = 2

So the solution to the system is x = 2, y = -4.

To match this solution with one of the graphs, we can plot the points (2, -4) and see which graph passes through that point.

Looking at the answer choices:

a) A line includes points (0, 6) and (2, 4). This line has a slope of -1 and a y-intercept of 6, so it does not pass through the point (2, -4).

b) A line includes points (0, 2) and (-2, 7). This line has a slope of -2.5 and a y-intercept of 2, so it also does not pass through the point (2, -4).

c) A line includes points (0, 1) and (1, -4). This line has a slope of -5 and a y-intercept of 1, so it does not pass through the point (2, -4).

d) A line includes points (0, 6) and (1, 3). This line has a slope of -3 and a y-intercept of 6, so it also does not pass through the point (2, -4).

Therefore, none of the given graphs match the system of equations.

User Beluchin
by
7.6k points