Final answer:
Connor's speed when he strikes the water is 7.67 m/s. The average force of water resistance experienced by his body is 133.6 N.
Step-by-step explanation:
To determine Connor's speed when he strikes the water, we can use the principle of conservation of energy. At the top of his trajectory, all of Connor's initial potential energy is converted into kinetic energy, since there is no air resistance. We can use the following equation to calculate his speed:
KE = PE
Where KE is the kinetic energy and PE is the potential energy. The equation for kinetic energy is KE = 0.5 * m * v^2, where m is the mass and v is the velocity. The equation for potential energy is PE = m * g * h, where g is the acceleration due to gravity and h is the height.
Calculating the potential energy at the top of the trajectory: PE = m * g * h = 76.0 kg * 9.8 m/s^2 * 3.00 m = 2234.4 J
Using the conservation of energy equation to calculate the speed: KE = PE = 0.5 * m * v^2 => v^2 = (2 * PE) / m = (2 * 2234.4 J) / 76.0 kg = 58.8 m^2/s^2 => v = sqrt(58.8 m^2/s^2) = 7.67 m/s
Therefore, Connor's speed when he strikes the water is 7.67 m/s.
To determine the average force of water resistance experienced by Connor's body, we can use the equation for drag force: Fdrag = 0.5 * rho * v^2 * A * Cd, where rho is the density of water, v is the velocity, A is the cross-sectional area, and Cd is the drag coefficient. Since we are given the depth and not the time, we can assume constant velocity. The drag coefficient for a human body in water is typically around 1.0. We can calculate the cross-sectional area of a person using the equation A = m / (rho * L), where L is the length of the person.
Calculate the cross-sectional area of a person: A = 76.0 kg / (1000 kg/m^3 * 2.15 m) = 0.035 m^2
Calculate the drag force: Fdrag = 0.5 * 1000 kg/m^3 * (7.67 m/s)^2 * 0.035 m^2 * 1.0 = 133.6 N
Therefore, the average force of water resistance experienced by Connor's body is 133.6 N.