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Determine the pressure (in atm) of a 7.16-g sample of He gas at 692 K in a container with a volume of 55.9 L.

1 Answer

5 votes

Answer:

1.82 atm

Step-by-step explanation:

Ideal gas law

P=nRT/V

1) solve for n which is moles

7.16 / 4 = 1.79 mole He

2)

n=1.79

R=0.0821

T=692 K

V=55.9

P=1.79 X 0.0821 X 692 / 55.9 =1.82 atm

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