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Construct a normal probability plot for the following sample of observations on coating thickness for low-viscosity paint.

0.82 0.88 0.88 1.06 1.09 1.14 1.30 1.33
1.48 1.50 1.57 1.64 1.64 1.70 1.76 1.83
Determine the z percentile associated with each sample observation. (Round your answers to two decimal places.)
I have the answers below but I don't know how they were computed. z = (X - ?) / ? does not provide the correct value. Can someone provide how the answers below were computer?
z percentile .82 = -1.86
z percentile .88 = -1.32
z percentile .88 = -1.32
z percentile 1.06 = -0.78
z percentile 1.09 = -0.58
z percentile 1.14 = -0.40
z percentile 1.30 = -0.24
z percentile 1.33 = -0.08
z percentile 1.48 = 0.08
z percentile 1.50 = 0.24
z percentile 1.57 = 0.40
z percentile 1.64 = 0.58
z percentile 1.64 = 0.58
z percentile 1.70 = 1.01
z percentile 1.76 = 1.32
z percentile 1.83 = 1.86

User Elettra
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1 Answer

3 votes

Final answer:

The z-score percentiles in the provided list were obtained by using rank-based z-scores that consider the rank of each observation relative to the entire dataset. Percentiles are calculated, and then the corresponding z-scores are found using a z-table or calculator functions like invNorm.

Step-by-step explanation:

To construct a normal probability plot and determine the z percentiles for each observation, we typically use the formula z = (X - μ) / σ, where X is the sample observation, μ is the mean, and σ is the standard deviation. However, the values provided do not seem to match this method, suggesting a different approach, most likely involving the use of rank-based z-scores.

In creating a normal probability plot with rank-based z-scores, you first must rank the observations from smallest to largest. Then for each observation, you calculate the cumulative probability using the formula (i - 0.5) / n, where i is the rank of the data point and n is the sample size. This probability value corresponds to the percentile of the observation. You must then use the standard normal distribution to find the z-score that corresponds to this cumulative probability.

Tools like a z-table, calculator functions like invNorm, or statistical software can find the z-score corresponding to a given percentile. As stated in your provided reference, invNorm(0.975,0,1) can be used for a cumulative probability of 0.975, which gives you the 97.5th percentile z-score.

It seems your provided z-score percentiles were calculated with a method that takes rank into account, which explains why the standard z-score formula did not match.

User Soumojit Ghosh
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8.1k points