162k views
3 votes
Construct a normal probability plot for the following sample of observations on coating thickness for low-viscosity paint.

0.82 0.88 0.88 1.06 1.09 1.14 1.30 1.33
1.48 1.50 1.57 1.64 1.64 1.70 1.76 1.83
Determine the z percentile associated with each sample observation. (Round your answers to two decimal places.)
I have the answers below but I don't know how they were computed. z = (X - ?) / ? does not provide the correct value. Can someone provide how the answers below were computer?
z percentile .82 = -1.86
z percentile .88 = -1.32
z percentile .88 = -1.32
z percentile 1.06 = -0.78
z percentile 1.09 = -0.58
z percentile 1.14 = -0.40
z percentile 1.30 = -0.24
z percentile 1.33 = -0.08
z percentile 1.48 = 0.08
z percentile 1.50 = 0.24
z percentile 1.57 = 0.40
z percentile 1.64 = 0.58
z percentile 1.64 = 0.58
z percentile 1.70 = 1.01
z percentile 1.76 = 1.32
z percentile 1.83 = 1.86

User Elettra
by
8.3k points

1 Answer

3 votes

Final answer:

The z-score percentiles in the provided list were obtained by using rank-based z-scores that consider the rank of each observation relative to the entire dataset. Percentiles are calculated, and then the corresponding z-scores are found using a z-table or calculator functions like invNorm.

Step-by-step explanation:

To construct a normal probability plot and determine the z percentiles for each observation, we typically use the formula z = (X - μ) / σ, where X is the sample observation, μ is the mean, and σ is the standard deviation. However, the values provided do not seem to match this method, suggesting a different approach, most likely involving the use of rank-based z-scores.

In creating a normal probability plot with rank-based z-scores, you first must rank the observations from smallest to largest. Then for each observation, you calculate the cumulative probability using the formula (i - 0.5) / n, where i is the rank of the data point and n is the sample size. This probability value corresponds to the percentile of the observation. You must then use the standard normal distribution to find the z-score that corresponds to this cumulative probability.

Tools like a z-table, calculator functions like invNorm, or statistical software can find the z-score corresponding to a given percentile. As stated in your provided reference, invNorm(0.975,0,1) can be used for a cumulative probability of 0.975, which gives you the 97.5th percentile z-score.

It seems your provided z-score percentiles were calculated with a method that takes rank into account, which explains why the standard z-score formula did not match.

User Soumojit Ghosh
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories