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Jamal sold hotdogs at a recent basketball game. Each hotdog sold for $3.50. In total, Jam

sold $98 worth of hot dogs. Let n be the number of hotdogs that Jamal sold.
Set up an equation that models the information given in this problem.

1 Answer

1 vote

Answer:The concession stand sold

46

hot dogs and

32

hamburgers.

Step-by-step explanation:

The first thing to do in algebraic problems is assign variables to things we don't know, so let's start there:

We don't know how many hot dogs the concession stand sold, so we will call that number

d

.

We don't know how many hamburgers the concession stand sold, so we will call that number

h

.

Now we translate the statements into algebraic equations:

The number of hot dogs and hamburgers that were sold is

78

, so

d

+

h

=

78

.

If each hot dog is sold for

1.25

, then the total revenue from hot dogs is given by

1.25

d

. In the same way, the total revenue from hamburgers is

1.50

h

. The total revenue from both hot dogs and hamburgers should be the sum of these, and since we are told the total revenue is

105.50

, we can say

1.25

d

+

1.5

h

=

105.5

.

We now have a system of two linear equations:

d

+

h

=

78

1.25

d

+

1.5

h

=

105.5

We can solve it using several methods, though I'm going to go with substitution. Use the first equation to solve for

d

:

d

+

h

=

78

d

=

78

h

Now plug this in for

d

in the second equation:

1.25

d

+

1.5

h

=

105.5

1.25

(

78

h

)

+

1.5

h

=

105.5

Solving for

h

, we have:

97.5

1.25

h

+

1.5

h

=

105.5

0.25

h

=

8

h

=

8

.25

h

=

32

Since

h

+

d

=

78

,

32

+

d

=

78

d

=

46

Step-by-step explanation:

User LaserBeak
by
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