Question

F(x)=3x^2+12+11 in vertex form

Answer 1

Answer:x-coordinate of vertex:

x = -b/(2a) = -12/-6 = 2

y-coordinate of vertex:

y(2) = -12 + 24 - 11 = 1

Vertex form:

y = -3(x - 2)^2 + 1

Check.

Develop y to get back to standard form:

y = -3(x^2 - 4x + 4) + 1 = -3x^2 + 12x - 11.

Explanation:

Answer 2

y = -3(x - 2)^2 + 1. Explanation: x-coordinate of vertex: x = -b/(2a) = -12/-6 = 2 y-coordintae of vertex: y(2) = -12 + 24 - 11 = 1

Explanation: