Question

Find the first five terms of the sequence a(n)=3n-1

Answer 1

-1, 2, 5 , 8 , 11 or 2, 5, 8, 11 , 14

Explanation:

Assume n starts from 0

a(0) = 3 (0) -1 = -1
a(1) = 3 (1) -1 = 2
a(2) = 3 (2) -1 = 5
a(3) = 3 (3) -1 = 8
a(4) = 3 (4) -1 = 11

notice If we Assume n starts from 1

a(1) = 3 (1) -1 = 2
a(2) = 3 (2) -1 = 5
a(3) = 3 (3) -1 = 8
a(4) = 3 (4) -1 = 11
a(5)= 3 (5) -1 = 14

Notice a sequence can start from any N. But the most common ones are n=0 or n=1