Question

HELP MEEEEEEEEEE PLS

If f(n) = n2 - 2n, which of the following options are correct?

Select all that apply.
f(2) = 0
f(-2) = 0
f(1) = 3
f(5) = 35
f(-4) = 24

Answer 1

Answer: A f(2)=0 I think

Answer 2

f(2) = 0

f(-4) = 24

Explanation:

`\hookrightarrow \: { \tt{ \sf{f(n) = {n}^(2) - 2n }}}`

When n is 2 ✔

`\dashrightarrow \: { \tt{f(2) = {(2)}^(2) - (2 * 2) = 4 - 4 = 0}} \\`

When n is -2 ✖

`\dashrightarrow { \tt{ {( - 2)}^(2) - (2 * - 2) = 4 + 4 = 8 }}`

When n is 1 ✖

`\dashrightarrow{ \tt{f(1) = {(1)}^(2) - (2 * 1) = - 1 }}`

When n is 5 ✖

`\dashrightarrow{ \tt{f(5) = {(5)}^(2) - (2 * 5) = 15}}`

When n is -4 ✔

`\dashrightarrow{ \tt{f( - 4) = {( - 4)}^(2) - (2 * - 4) }} \\ { \tt{ = 16 + 8}} \\ { \tt{ = 24}}`