The electric field strength near an infinite sheet of charge density σ is given by E = σ/2ε0, where ε0 is the electric constant.
The force on the proton due to the electric field of the sheet is F = qE, where q is the charge of the proton.
The work done by the sheet on the proton is W = Fd, where d is the distance traveled by the proton before reaching its turning point.
When the proton has reached its turning point, its kinetic energy is zero, so the work done by the electric field of the sheet must equal the initial kinetic energy of the proton, which is given by KE = (1/2)mv^2, where m is the mass of the proton and v is its initial velocity.
Setting these two expressions for work equal to each other, we have:
F d = (1/2)mv^2
Substituting F = qE and E = σ/2ε0, we get:
qd/2ε0 = (1/2)mv^2
Solving for d, we get:
d = mv^2/(qσε0)
Substituting the given values for m, v, q, and σ, and the value of ε0 from the constants, we get:
d = (1.67x10^-27 kg)(2.30x10^6 m/s)^2/(1.60x10^-6 C/m^2)(2ε0) ≈ 1.59x10^-5 m
Therefore, the proton travels a distance of approximately 1.59x10^-5 meters before reaching its turning point.