Question

B) Verify by calculation what volume of the base it should take to neutralize 50.0 mL of 0.1 M HCl (aq)

with 0.1 M NaOH(aq).

Answer 1

50 ml

Step-by-step explanation:

n = moles

c = concentration

v = volume

n = c × v

HCl + NaOH --> NaCl + H2O

HCl:

50 ml = 50 cm³ = 0.05 dm³

n = 0.05 × 0.1

n = 0.005

Ratio of HCl to NaOH:

HCl : NaOH

Based on reaction equation:

1 : 1

0.005 : x

x = 0.005

NaOH:

0.005 = 0.1 × v

v = 0.05

0.05 dm³ = 50 cm³ = 50 ml