Answer:
So 3 blue buckets and 4 white buckets were purchased
Explanation:
We can solve this by algebra
Let B = number of blue buckets bought
Let W = number of white buckets bought
Total buckets bought:
B + W = 7 (1)
Each blue bucket can hold 2 gallons of water
So B blue buckets can hold 2B gallons of water
Each white bucket can hold 5 gallons of water
So W white buckets can hold 5W gallons of water
Totally they can hold
2B + 5W gallons
We are given that they both can hold 26 gallons of water
So our second equation is
2B + 5W = 26 (2)
By eliminating one of the variable terms we can solve for the other variable term
Let's eliminate the term for variable B
Multiply equation (1) by 2
(1) x 2 ==> 2(B + W) = 2(7)
2B + 2W = 14 (3)
Subtract (3) from (2); B terms are same so they cancel out
(2) - (3):
2B + 5W = 26

2B + 2W = 14
---------------------
0 + 3W = 12
------------------------
3W = 12
W = 12/3
W = 4
Substitute W= 4 in equation 1
B + W = 7
=> B + 4 = 7
B = 3
So 3 blue buckets and 4 white buckets were purchased