Answer: The two positive numbers that satisfy the given requirements are 25 and 50.
Explanation:
Let's call the two positive numbers x and y. We want to maximize their product while satisfying the condition that "the sum of the first and twice the second is 100", or mathematically:
x + 2y = 100
We can use algebra to solve for one of the variables in terms of the other:
x = 100 - 2y
Now we want to maximize the product xy:
xy = x(100 - 2y) = 100x - 2xy
Substituting x = 100 - 2y:
xy = (100 - 2y)y = 100y - 2y^2
To find the maximum value of this expression, we can take the derivative with respect to y and set it equal to zero:
d(xy)/dy = 100 - 4y = 0
Solving for y gives:
y = 25
Substituting y = 25 into the equation x + 2y = 100, we get:
x + 2(25) = 100
x = 50
Therefore, the two positive numbers that satisfy the given requirements are x = 50 and y = 25, and their product is:
xy = 50(25) = 1250