Question

Given that 4 NH3 + 5 O2 → 4 NO + 6 H2O, if 3.00 mol NH3 were made to react with excess of oxygen gas, the amount of H2O formed would be

Answer 1

Answer:

x mol H2O = 4.50 mol H2O

Explanation:

From the balanced equation, we can see that for every 4 moles of NH3 that react, 6 moles of H2O are formed. Therefore, we can use a proportion to find the amount of H2O that would be formed if 3.00 mol of NH3 reacted:

4 mol NH3 : 6 mol H2O = 3.00 mol NH3 : x mol H2O

Solving for x, we get:

x mol H2O = (6 mol H2O / 4 mol NH3) * 3.00 mol NH3
x mol H2O = 4.50 mol H2O

Therefore, if 3.00 mol of NH3 were made to react with excess oxygen gas, 4.50 mol of H2O would be formed.