Question

4. Find the solution of the following equations:

a) x + 5 = 15
b) 12 – y = 12
c) 3a = 27
d) y/4 = 20
e) 2 + y = 0

Answer 1

a) x + 5 = 15

Subtracting 5 from both sides, we get:

x + 5 - 5 = 15 - 5

x = 10

Therefore, the solution is x = 10.

b) 12 – y = 12

Subtracting 12 from both sides, we get:

12 - 12 - y = 12 - 12

-y = 0

Multiplying both sides by -1, we get:

y = 0

Therefore, the solution is y = 0.

c) 3a = 27

Dividing both sides by 3, we get:

a = 9

Therefore, the solution is a = 9.

d) y/4 = 20

Multiplying both sides by 4, we get:

y = 80

Therefore, the solution is y = 80.

e) 2 + y = 0

Subtracting 2 from both sides, we get:

y = -2

Therefore, the solution is y = -2.