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Suppose the number of dropped footballs for a wide receiver, over the course of a season, are normally distributed with a mean of 16 and a standard deviation of 12. What is the z-score for a wide receiver who dropped 13 footballs over the course of a season?

A. -3
B. -1.5
C. 1.5
D. 3

User Kulukrok
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1 Answer

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The z-score formula is:

z = (x - μ) / σ

where x is the observed value, μ is the mean, and σ is the standard deviation.

Substituting the given values:

z = (13 - 16) / 12
z = -0.25

Therefore, the z-score for a wide receiver who dropped 13 footballs over the course of a season is closest to option A: -3.
User Newmaniese
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