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4 votes
If the change in internal energy = 1714J, specific

heat capacity = 49J/°C/kg, and mass = 38kg,
what is the temperature change experienced?
Give your answer to 2 decimal places.

1 Answer

4 votes

Answer:

0.92°C

Step-by-step explanation:

C = change in Q/m × change in T

so

change in T = change in Q/C ×m

C= 49

m= 38

change in Q= 1714

then

= 1714/49 × 38

= 1714/1862

= 0.92°C

rounded off to 2 d.p

User Zhro
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