Question

If the change in internal energy = 1714J, specific

heat capacity = 49J/°C/kg, and mass = 38kg,
what is the temperature change experienced?
Give your answer to 2 decimal places.

Answer 1

0.92°C

Step-by-step explanation:

C = change in Q/m × change in T

so

change in T = change in Q/C ×m

C= 49

m= 38

change in Q= 1714

then

= 1714/49 × 38

= 1714/1862

= 0.92°C

rounded off to 2 d.p