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Molar Mass

What is the molar mass of a gas that has a density of 1.02 g/L at 0.990 atm pressure and 37 degrees C

User HelenM
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Answer:

The molar mass of the gas is approximately 32.0 g/mol.

Step -by-step explanation:

To calculate the molar mass of the gas, we need to use the ideal gas law, which relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas:

PV = nRT

where R is the gas constant.

To solve for the number of moles, we can rearrange this equation as:

n = PV/RT

We are given the density (ρ) of the gas, which is related to the molar mass (M) and the volume by:

ρ = PM/RT

Rearranging this equation, we can solve for the molar mass:

M = ρRT/P

Now we can substitute in the given values:

ρ = 1.02 g/L
T = 37°C + 273.15 = 310.15 K
P = 0.990 atm

We also need to convert the density from g/L to kg/m³:

ρ = 1020 g/m³

Using the gas constant R = 0.08206 L atm/mol K, we get:

M = (1020 g/m³) (0.08206 L atm/mol K) (310.15 K) / (0.990 atm)
M ≈ 32.0 g/mol

Therefore, the molar mass of the gas is approximately 32.0 g/mol.
User NiL
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