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What if the equation of the line that passes through (-4,5) and is parallel to the line 4x+2y=10

User Sagistic
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1 Answer

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Answer: y = -2x -3

Step by step explanation

First, we find the gradient of the line 4x + 2y = 10 by making y the subject of the formula.

4x + 2y = 10

2y = 10 - 4x which is the same as 2y = -4x + 10

Divide each term by 2

2y/2 = -4x/2 + 10/2

y = -2x + 5

From the equation, the gradient (coefficient of x) is -2

Since the line is parallel to 4x+2y=10, therefore the gradient of the lines are the same

The equation of the line can be gotten from y - y1 = m(x -x1)

where y1 = 5, x1 = -4 and m = -2

Therefore subtitiuiting into y - y1 = m(x -x1)

y - 5 = -2(x-(-4))

y - 5 = -2(x + 4)

y - 5 = -2x - 8

y = -2x -8 + 5

y = -2x -3

you can see that the gradients are the same (coefficent of x = -2)

User Tinyd
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