Question

A little boy slides a disc on the floor without tumbling and with an initial velocity of 2.5m/s. If the coefficient of kinetic friction between the disc and the floor is 0.25, determine horizontal distance the disc travels on the floor before coming to rest.

Answer 1

Step-by-step explanation:

Ff = mg ( .25)

KE = 1/2 m (2.5)^2

Work of friction mg (.25) X (d) must equal the KE for the disc to stop

mg(.25)(d) = 1/2 m ( 2.5)^2 <=== Divide both sides by 'm'

g (.25)(d) = 1/2 ( 2.5)^2

9.81 (.25) d = 1/2 ( 2.5)^2

d = 1.27 m