Question

Please help me with my math!

Answer 1

y= 2(x+4)^2 -6

Explanation:

y= 2x^2 + 16x + 26

It is in the form y= ax^2 + bx + c

To rewrite in the form y=a(x-p)^2 + q

We need to fin p and q. We already have a in the original equation.

In y= 2x^2 + 16x + 26, a=2.

The formula say that: p=-b/2a

p= -16/(2*2)

p=-16/4

p=-4

In the formula, we replace a and y= 2(x-(-4))^2 +q

Obtaining, y= 2 (x+4)^2 + q

Now, to find q we need to obtain a point from the original equation. Commonly the y-intercept. In the form y= ax^2 + bx + c ; C is the y-intercept.

y-intercept: (0,c)

Therefore, in y= 2x^2 + 16x + 26

y-intercept: (0,26)

In the equation we already have:

y= 2(x+4)^2 +q

26= 2(0+4)^2 + q

26=2(4)^2 +q

26= 2(16) + q

26= 32 + q

-6 = q

Joining all the results, we obtain:

y= 2(x+4)^2 -6

Answer 2

To rewrite the quadratic equation in the form y = a(x - p)²+q, we need to complete the square.

y = 2x^2 + 16x + 26

y = 2(x^2 + 8x) + 26

y = 2(x^2 + 8x + 16 - 16) + 26 // Adding and subtracting (8/2)^2 = 16 inside the parentheses

y = 2((x + 4)^2 - 16) + 26

y = 2(x + 4)^2 - 32 + 26

y = 2(x + 4)^2 - 6

Therefore, the quadratic equation y = 2x ^ 2 + 16x + 26 rewritten in the form y = a(x - p)²+q is y = 2 * (x + 4) ^ 2 - 6, so the answer is D