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24 votes
24 votes
What is the distance between the points (-2,3) and (5, -1)?

User Kevin Van Mierlo
by
3.4k points

2 Answers

13 votes
13 votes

Answer:

√65

Explanation:

Compute the Euclidean distance between the following points:

p_1 = (-2, 3) and p_2 = (5, -1)

The Euclidean distance between points (x_1, y_1) and (x_2, y_2) is:

sqrt((x_1 - x_2)^2 + (y_1 - y_2)^2)

Substitute (x_1, y_1) = (-2, 3) and (x_2, y_2) = (5, -1):

= sqrt((-2 - 5)^2 + (--1 + 3)^2)

(-1)^2 = 1:

= sqrt((-2 - 5)^2 + (1 + 3)^2)

-2 - 5 = -(2 + 5):

= sqrt((-(2 + 5))^2 + (3 + 1)^2)

2 + 5 = 7:

= sqrt((-7)^2 + (3 + 1)^2)

Multiply each exponent in -7 by 2:

= sqrt((-1)^2×7^2 + (3 + 1)^2)

7^2 = 49:

= sqrt((-1)^2×49 + (3 + 1)^2)

(-1)^2 = 1:

= sqrt(49 + (3 + 1)^2)

3 + 1 = 4:

= sqrt(49 + 4^2)

4^2 = 16:

= sqrt(49 + 16)

| 1 |

| 4 | 9

+ | 1 | 6

| 6 | 5:

Answer: √65

User SashaQbl
by
2.9k points
10 votes
10 votes
The distance between the points (-2,3) and (5.-1) is 10
User Willvv
by
3.0k points