Question

Jaxon is flying a kite, holding his hands a distance of 3.25 feet above the ground and

letting all the kite's string play out. He measures the angle of elevation from his hand
to the kite to be 24°. If the string from the kite to his hand is 105 feet long, how many
feet is the kite above the ground? Round your answer to the nearest tenth of a foot if
necessary.

Answer 1

Answer: 46.0 ft

Explanation:

`\text{sin} \ 24^o=(x)/(105)`

`x=105 \ \text{sin 24}^o`

So, the distance above the ground is
`\text{105 sin} \ 24^o+3.25\thickapprox \boxed{46.0 \ \text{ft}}`