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Write the equation of a line perpendicular to `y=3` that goes through the point (-5, 3).

User Vkraemer
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6 votes

Answer:

x= -5

Explanation:

The perpendicular line is anything with x= __.

x= -5 however, will go through the point (-5, 3) and that is our answer.

User Fahim
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4 votes

Answer:

The equation of a line perpendicular to y=3 that goes through the point (-5, 3) is: x = -5.

Explanation:

To find the equation of a line perpendicular to y=3 that goes through the point (-5, 3), we need to remember that the slope of a line perpendicular to another line is the negative reciprocal of the slope of the original line.

The equation y=3 is a horizontal line that goes through the point (0,3), and its slope is zero. The negative reciprocal of zero is undefined, which means that the line perpendicular to y=3 is a vertical line.

To find the equation of this vertical line that goes through the point (-5, 3), we can start with the point-slope form of a linear equation:

y - y1 = m(x - x1)

where m is the slope of the line and (x1, y1) is a point on the line. Since the line we want is vertical, its slope is undefined, so we can't use the point-slope form directly. However, we can still write the equation of the line using the point (x1, y1) that it passes through. In this case, (x1, y1) = (-5, 3).

The equation of the vertical line passing through the point (-5, 3) is:

x = -5

This equation tells us that the line is vertical (since it doesn't have any y term) and that it goes through the point (-5, 3) (since it has x=-5).

So, the equation of a line perpendicular to y=3 that goes through the point (-5, 3) is x = -5.

User Hyleaus
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