Answer:
The equation of a line perpendicular to y=3 that goes through the point (-5, 3) is: x = -5.
Explanation:
To find the equation of a line perpendicular to y=3 that goes through the point (-5, 3), we need to remember that the slope of a line perpendicular to another line is the negative reciprocal of the slope of the original line.
The equation y=3 is a horizontal line that goes through the point (0,3), and its slope is zero. The negative reciprocal of zero is undefined, which means that the line perpendicular to y=3 is a vertical line.
To find the equation of this vertical line that goes through the point (-5, 3), we can start with the point-slope form of a linear equation:
y - y1 = m(x - x1)
where m is the slope of the line and (x1, y1) is a point on the line. Since the line we want is vertical, its slope is undefined, so we can't use the point-slope form directly. However, we can still write the equation of the line using the point (x1, y1) that it passes through. In this case, (x1, y1) = (-5, 3).
The equation of the vertical line passing through the point (-5, 3) is:
x = -5
This equation tells us that the line is vertical (since it doesn't have any y term) and that it goes through the point (-5, 3) (since it has x=-5).
So, the equation of a line perpendicular to y=3 that goes through the point (-5, 3) is x = -5.