Answer:
y = -1/3x +6
Explanation:
You want the equation of the line through the point (3, 5) and perpendicular to y = 3x +2.
Slope-intercept form
The slope-intercept form of the equation of a line is ...
y = mx +b
where m is the slope, and b is the y-intercept.
Comparing this to the given equation, we see that m=3 for the given line.
Perpendicular lines
The slopes of perpendicular lines are opposite reciprocals of one another. This means the slope of the line we want is ...
desired slope = -1/m = -1/3
Y-intercept
The slope-intercept equation above can be solved for b to give ...
b = y -mx
Then the y-intercept for the line we want is ...
b = 5 -(-1/3)(3) = 5 +1 = 6
The equation of the desired line is y = -1/3x +6.
__
Additional comment
Once you understand how to find the slope of the given line and of the desired line, you can write down the desired equation in point-slope form.
Given slope = 3; perpendicular slope = -1/3
Point-slope equation: y -k = m(x -h) . . . . line through (h, k) with slope m
y -5 = -1/3(x -3) . . . . . line through (3, 5) with slope -1/3
The only "work" required is to rearrange this equation to whatever form you may want. In standard form it is x +3y = 18.