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3 votes
You are carrying a 6.00 kg

bag at a height of 3.20 m

above the level floor of a 4.220

mlong room at a constant
velocity of 0.60 m s'. How
much work do you do on the
bag in moving across the

room?

OA. 247J

O B. 182J

Oc.0J

OD.

318 J

O E. 34J

1 Answer

1 vote

Answer:

The answer is A) 247 J, which is the closest to the calculated value.

Step-by-step explanation:

To calculate the work done on the bag, we need to use the formula:

work = force x distance x cos(theta)

where force is the weight of the bag (mg), distance is the length of the room, and theta is the angle between the force and the displacement (which is zero since the force and displacement are in the same direction).

First, let's calculate the force:

force = weight of the bag = mg = (6.00 kg) x (9.81 m/s^2) = 58.86 N

Next, let's calculate the distance:

distance = length of the room = 4.220 m

Now, we can calculate the work done:

work = (58.86 N) x (4.220 m) x cos(0) = 247.68 J

User Chris Kennedy
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