Question

For the reaction 2AI + 3H₂O → Al₂O3 + 3H₂, how many moles of Al2O3 are produced from 115 g of AI?

8.54 mol Al₂O3
4.27 mol Al₂O3
2.13 mol Al₂O3
1550 mol Al₂O3

Answer 1

2.13 mol Al2O3

Step-by-step explanation:

mol of Al=
115g/ 26.9 g/mol

4.275 mol of Al

The multiply by mol ratio

4.275 * 1 mol al2o3/2 mol Al

2.13

Answer 2

From 115 g of Al, 2.13 moles of Al2O3 will be produced based on the stoichiometry of the reaction 2Al + 3H2O → Al2O3 + 3H2 and the molar mass of Al (26.98 g/mol).

Step-by-step explanation:

Calculating Moles of Aluminum Oxide Produced

To determine how many moles of Al2O3 are produced from 115 g of Al, you can follow these steps:

First, you need to calculate the number of moles of Al that 115 g represents. The molar mass of Al is approximately 26.98 g/mol.

Divide the mass of Al by its molar mass to find the number of moles: 115 g ÷ 26.98 g/mol = 4.26 moles of Al.

Next, look at the balanced chemical equation: 2Al + 3H2O → Al2O3 + 3H2. This shows that 2 moles of Al produce 1 mole of Al2O3.

Since you have 4.26 moles of Al, divide this number by 2 to determine the moles of Al2O3 formed: 4.26 moles of Al ÷ 2 = 2.13 moles of Al2O3.

Therefore, from 115 g of Al, 2.13 moles of Al2O3 will be produced.