Question

Does anyone know the what all of the y's are

Answer 1

Explanation:

You need solve for y:

`y-4=3(x-1)\\y-4=3x-3\\y=3x-3+4\\\therfore \quad y=3x+1`

now, evaluate in each x's value, for example:

`y=3(-2)+1\\\therefore \quad y=-5`

This, is the value of
`y`, when
`x=-2`

Therefore:

`\begin{tabular} \cline{0-1}x & y \\ \cline{0-1}-2 & -5 \\ -1 & -2\\ 0& 1 \\ 1& 4\\ 2& 7\\ \cline{0-1}\end{tabular}`

`\text{-B$\mathfrak{randon}$VN}`